Question

A 60 kg student runs up to the second floor of the school 8 m high in 12 s. What is his power
output? (g = 98 m ) full solution please ​

Answer 1

Answer:

hope this will help you.

Answer 2

Answer:

• Power output of body = 392 joule/sec

Explanation:

Given :

• Mass of student, m = 60 kg
• height to which student runs (second floor of school), h = 8 m
• Time for which he runs, t = 12 s
• Acceleration due to gravity taken, g = 9.8 ms⁻²

To find :

• Power output of student, P = ?

Knowledge required :

• Formula to calculate potential energy

       P.E. = m g h

[ where P.E. is the potential energy of body having mass m , acceleration due to gravity g and vertical height to be covered is h ]

• Formula to calculate Power

      P = E / t

[ where P is power, E is energy and t is time ]

Solution :

Calculating potential energy of student consumed to reach the second floor of the school

→ P.E. = m g  h

→ P.E. = ( 60 ) × ( 9.8 ) × ( 8 )

→ P.E. = 4704  Joules

Calculating power output of the student

→ P = E / t

→ P = 4704 / 12

→ P = 392 Watt or 392 Joule / sec

Therefore,

• Power output of boy will be 392 joule/sec .