Question

A 60 litre solution of alcahol and water contains 20 litre of alcahol. How much alcahol must be added to produce a solution of 50% alcahol?​

Answer 1

Answer:

Total solution = 60 L

Alcohol in solution = 20 L

Let x L alcohol must be added to produce 50% alcohol.

Then alcohol in solution at last = (x + 20) L

Total solution at last = (60 + x) L

Now,

     Alcohol at last is equal to 50% of total solution.

     x + 20 = 50(60 + x)/100

 ⇒ x + 20 = (60 + x)/2

 ⇒ x + 20 = 30 + x/2

 ⇒ x - x/2 = 30 - 20

 ⇒ (2x - x)/2 = 10

 ⇒ x/2 = 10

 ⇒ x = 10 * 2

 ⇒ x = 20

Therefore, 20L of alcohol must be added in 60L solution to get 50% alcohol in the solution.

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