a compound h2x with molar weight o 80g is dissolved in a solvent having density of 0.4 g per mole assuming no change in volume upon dissociation the molarity of 3.2 molar solution is
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1
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Explanation:
In 3.2 molar solution,
We have amount of solute = 3.2 mol
Volume of solution = 1.0 L
Since there occurs no change in volume on dissolving solute,
Volume of solvent = 1L
Mass of solvent = (1.0L)(0.4 gmL-1)
= (103mL)(0.4 gmL-1)
=400 g =0.4kg
Molality of the solution = 3.2/0.4 =8molkg-1
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