A bullet of mass 10g is fired from gun of mass 1kg .if the gun recoil with a speed of 5s-1 then the muzzle speed of bulletis
Answers
By applying law of conservation of momentum,
Total Initial momentum = Total Final momentum
Initial momentum of gun = MU = 1×0 = 0
Initial momentum of bullet = mu = 10/1000 × u = u/100
Final momentum of gun = MV = 1×5 = 5
Final momentum of bullet = mv = 10/1000×0 = 0
Therefore,
MU+mu = MV+mv
0+u/100 = 5+0
u/100 = 5
u = 5×100 = 500m/s
Therefore, muzzle speed of the bullet is 500m/s
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The muzzle velocity of the bullet fired would be 500 m/s
1) According, to the third law of motion by newton, every action has an equal and opposite reaction.
2) so, if the bullet exerts a momentum when going forward, same amount of momentum will push the gun backward
3) Hence, the momentum of both would be equal
10 g * v = 1000 g * 5 m/s
v = 500 m/s
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