A 60 litre tank was full of petrol. Peter used 30% of it and poured the rest into a50 litre tank
(1) What percent of 50 litre tank was filled with petrol?
(ii) If Peter used 2.8 litres of petrol daily, what percent of petrol in the 50 litre tank would be used in 10 days?
Answers
Answer:
1) 30% of 60L = 18
remaining = 42 L
in 50L tank , 42/50×100 = 84%
2) petrol used daily = 2.8L
10 days =2.8×10
=28L
percentage = 28/42×100
=66.6 %.
Hope it helps you.
(i) The percentage of petrol is 84%
(i) The percentage of petrol is 84% (ii) The percentage of petrol is 58.3%
GIVEN
A 60 litre tank was full of petrol. Peter used 30% of it and poured the rest into a 50 litre tank
TO FIND
(1) What percent of 50 litre tank was filled with petrol?
(ii) If Peter used 2.8 litres of petrol daily, what percent of petrol in the 50 litre tank would be used in 10 days?
SOLUTION
We can simply solve the above problem as follows;
Volume of tank = 60litre
Percentage of petrol used = 30%
Volume of petrol used = 30% of 60
= 0.3 × 60 = 18 litres
Volume of petrol left = 60 - 18 = 42 litres.
Volume of second tank = 50 litres.
Percentage of 50 litres tank filled = (42/50)×100 = 84%
(ii)
Volume of petrol used daily = 2.8 litres
Petrol used in 10 days = 2.8 × 10 = 28 litres.
Percentage of milk used in 10 days = (28/42)×100
= 58.3%
Hence,The answers are as follows;
Hence,The answers are as follows; (i) The percentage of petrol is 84%
Hence,The answers are as follows; (i) The percentage of petrol is 84% (ii) The percentage of petrol is 58.3%
Hence,The answers are as follows; (i) The percentage of petrol is 84% (ii) The percentage of petrol is 58.3% #Spj2