Question

A 60 volt battery would spend 1200 Watts What power across the resistance of​

Answer 1

Answer: 3 ohm.

Explanation:

V= 60v, P= 1200W

I= P/V

I= 1200/60

I= 20A

So, the current= 20A

Now,

R= P/I^2

R= 1200/20*20

R= 3ohm

Hence, the Resistance= 3 ohm.

Answer 2

RESISTANCE OF CIRCUIT IS 3 Ohm.

Given:

• Potential difference = 60 volts
• Power = 1200 watts

To find::

Resistance in the circuit ?

Calculation:

Let's assume that resistance R is connected to a circuit with a battery providing potential difference of 60 V The net power dissipated in circuit is 1200 watt.

So, resistance is :

$\therefore \: W = \dfrac{ {V}^{2} }{R}$

$\implies \: R = \dfrac{ {V}^{2} }{W}$

$\implies \: R = \dfrac{ {(60)}^{2} }{1200}$

$\implies \: R = \dfrac{ 3600}{1200}$

$\implies \: R = 3 \: ohm$

So, resistance in circuit is 3 ohm.