A 60-watt light bulb is connected to a circuit using 120 volts. What is the resistance in the circuit?
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Power P=V^2/R
R=V^2/P
R=(120)^2/60
=14400/60
=240 ohm
R=V^2/P
R=(120)^2/60
=14400/60
=240 ohm
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