a 600 grams of sugur solutions contains 50% sugur. how in (grams) must added so that the new mixture contains 70% sugur?
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Answered by
0
Answer:
I too have same dought
Step-by-step explanation:
in chemistry
Answered by
0
Step-by-step explanation:
40
×600=240
∴240g of sugar is present is 600g of solution.
600+x
240+x
=
2
1
(50% of solution)
480+2x=600+x
2x−x=600−480
x=120
∴120g of sugar must be added.
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