A 600 kg car is at rest and then Acceleration to 5 m/s
What is itтАЩs original kinetic energy
What is itтАЩs final kinetic energy
How much work was used
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Here's your answer...
m = 600 kg
u = 0 (as the car was at rest initially)
v = 5 m/s
Initial kinetic energy = ½mu²
= ½×600×0
= 0
Final kinetic energy = ½mv²
= ½×600×25
= 7500 J
By the work-energy theorem,
Work done = change in kinetic energy
W = final KE - initial KE
= 7500 - 0
= 7500 J
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Here's your answer...
m = 600 kg
u = 0 (as the car was at rest initially)
v = 5 m/s
Initial kinetic energy = ½mu²
= ½×600×0
= 0
Final kinetic energy = ½mv²
= ½×600×25
= 7500 J
By the work-energy theorem,
Work done = change in kinetic energy
W = final KE - initial KE
= 7500 - 0
= 7500 J
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
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