Question

A 60hz ,320km lossless line has sending end voltage 1.0 pu.The receiving end voltage on no-load is

Answer 1

Answer:

BY F(net) = F(gravity)

=>ma = mgsin(90*-θ)

=>a = gcosθ

=>By s = ut + 1/2at^2

=>AB = 0 + 1/2 x gcosθ x t^2

=>t = √[2AB/gcosθ]

If perpendicular from B is meeting at the center

=>AB = √[R^2 +R^2]

=>AB = √2R

=>then t = √[2√2R/gcosθ]