Question

A light ray hits the pole of a thin biconvex lens as shown the angle made by emergent ray with optic axis will be

Answer 1

BY F(net) = F(gravity)

=>ma = mgsin(90*-θ)

=>a = gcosθ

=>By s = ut + 1/2at^2

=>AB = 0 + 1/2 x gcosθ x t^2

=>t = √[2AB/gcosθ]

If perpendicular from B is meeting at the center

=>AB = √[R^2 +R^2]

=>AB = √2R

=>then t = √[2√2R/gcosθ]