a 6kg sledge is travelling on a ice of speed 9 m/s when a 12 kg packet is dropped into it vertically the velocity of the slab will now be
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Answered by
11
using conservation of momentum
6*9 = 18v
v = 3m/s
aayushg1713:
Ok let me explain
yes pls
the mass is dropped in perpendicular direction this means that no external force acts on the sledge in the direction of its velocity. so external force in horizontal direction is 0 which means we can conserve initial and final momentum of the sledge.
got it
thank you
yo!
mark the answer as brainliest please !!
sure
how to do it?
when someone other answers it will show but thanks <3
Answered by
17
Answer:
4ms
Explanation:
m1=60
u1 =10
m2=90
v =?
u2=0
v= m1u1+m2u2 /m1+m2
= 600/150
=4
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