A 6ohm resistance wire is doubled up by folding calculate new resistance of wire
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Resistance=ρL/A
Here, Resistance=6ohm
Therefore,6=ρL/A
In second case, Resistance,R'=ρL'/A'
As the wire is doubled so L'=L/2, A'=2A
So new resistance,R'=ρL/4A=(1/4)ρL/A
But ρL/A=6
So, R'=6/4=1.5Ω
Hope it helps
Here, Resistance=6ohm
Therefore,6=ρL/A
In second case, Resistance,R'=ρL'/A'
As the wire is doubled so L'=L/2, A'=2A
So new resistance,R'=ρL/4A=(1/4)ρL/A
But ρL/A=6
So, R'=6/4=1.5Ω
Hope it helps
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