Question

a 6ohm resistance wire is doubled up by folding .calculate the new resistance of wire ..

Answer 1

Answer:

Resistance=ρL/A

Here, Resistance=6ohm

Therefore,6=ρL/A

In second case, Resistance,R'=ρL'/A'

As the wire is doubled so L'=L/2, A'=2A

So new resistance,R'=ρL/4A=(1/4)ρL/A

But ρL/A=6

So, R'=6/4=1.5Ω

Explanation:

Answer 2

HeRe Is Your Ans ⤵

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Resistance=ρL/A Here, Resistance=6ohm Therefore,6=ρL/

A

In second case, Resistance,R'=ρL'/A' As the wire is doubled so L'=L/2, A'=2A

So new resistance,R'=ρL/4A=(1/4)ρL/A But ρL/A=6 So, R'=6/4=1.5Ω

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