A 6ohm resistance wire is folded what is the new resistance
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wire doubled i THINK
Resistance=ρL/A
2, Resistance,R '=ρL '/A '
wire is doubled so L '=L/2, A '=2A
our resistance is now, R'=ρL/4A= (1/4)ρL/A
since ρL/A =6
∴R'=6/4=1.5Ω
I THINK
note since i cant dis play fractions i using/your answer is 1.5Ω
hope this helped
Resistance=ρL/A
2, Resistance,R '=ρL '/A '
wire is doubled so L '=L/2, A '=2A
our resistance is now, R'=ρL/4A= (1/4)ρL/A
since ρL/A =6
∴R'=6/4=1.5Ω
I THINK
note since i cant dis play fractions i using/your answer is 1.5Ω
hope this helped
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