Question

A parallel plate capacitor of capacitance c is chrged with the potential v it's then connected to anather uncharged capacitor having the same capacitance. find out the ratio of the energy stored in the combined system to that stored initially in the single capacitor

Answer 1

Hi ....dear..here is your solution...

Answer 2

Hey !!

Energy stored in a capacitor

                 U = 1/2 CV² (or) 1/2 q²/C

Capacitance of the parallel combination

              = C + C = 2C

Here, the total charge, Q remains the same

∴ Initial energy = 1/2 q²/C

and Final energy = 1/2 q²/2C

∴ Ratio of energies =  Final energy / Initial energy

           = 1/4.q²/C / 1/2

           = 2/4

            = 1/2

GOOD LUCK !!