A 6ohm resistance wire is tripled by folding . Calculate the new resistance of the wire ?
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Resistance=ρL/A Here, Resistance=6ohmTherefore,6=ρL/A In second case, Resistance,R'=ρL'/A' As the wire is doubled so L'=L/2, A'=2A So new resistance,R'=ρL/4A=(1/4)ρL/ABut ρL/A=6 So, R'=6/4=1.5Ω
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