Question

How many 176 resistors in parallel are required to carry 5A on a 220V line?​

Answer 1

Here is ur answer............

Hope it helps!!

Answer 2

Given: Individual resistance, R=176 Ω

I=5 A

V=220 V

Let Number Of Resistors Be x.

Then,

$[tex]R_{1} = R_{2} = ....... = R_{x} = R = 176$Ω .....(i)

For resistor in Parallel,

$\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}} +..... + \frac{1}{R_{x}}$ .....(ii)

From (i) and (ii).

$R_{eq} = \frac{176}{x}$ ......(iii)

By ohm's Law.

$V=IR_{eq}$

$220=5R_{eq}$ ......(iv)

Substituting (iii) in (iv)

$220 = 5* \frac{176}{x}$

$n=4$