Question

A 7.03 kg laundry bag is dropped from rest at an initial height of 5.88 m. The acceleration of gravity is −9.81 m/s2 . Use the value 5.98 × 1024 kg as the mass of Earth. What is the speed of Earth toward the bag just before the bag hits the ground? Answer in units of m/s.

Answer 1

In this numerical potential energy is converted into kinetic energy. We will use energy and work conversion formula to solve this numerical.

Formula: mgh = (MV^2)/2

Putting the values we get

7.03*9.8*5.88= ( 5.98*10^24*V^2 )* 0.5

V= 1.16*10^-11 m/s  

The speed of the earth towards the bag is  1.16*10^-11 m/s.