Math, asked by clashofclansnew, 1 year ago

find the h c f of k ,2k,3k,4k and 5k where k is any postive in tagar

Answers

Answered by Anonymous
1
☆HCF of k, 2k, 3k, 4k, 5k is k. ☆

Hope it helps u.☆☆
Answered by QuestionEverything
1
HCF of k, 2k, 3k, 4k and 5k is 'k' itself for any positive value of k.
HCF of k and 2k
2k=k×2+0
as remainder=0, Therefore, HCF = k, Similarly, For all cases, HCF = k
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