Physics, asked by Rano38, 5 months ago

A 7.0kg cannonball flying rightwards at 12m/s hits a stationary rock. the cannonball keeps moving in the same direction at 2.0m/s after collision but sends the rock flying 14m/s towards right. what os the mass of the rock?

step by step

Answers

Answered by rajgurukumar

Answer:

A 7.0kg cannonball flying rightwards at 12m/s hits a stationary rock. the cannonball keeps moving in the same direction

Answered by Mithalesh1602398

Answer:

The mass of the rock is 4.5 kg.

Explanation:

We can use the conservation of momentum to solve this problem. The total momentum of the system before the collision is equal to the total momentum after the collision. We can write this as:

m1v1 + m2v2 = m1v1' + m2v2'

where m1 and v1 are the mass and velocity of the cannonball before the collision, m2 and v2 are the mass and velocity of the rock before the collision, and v1' and v2' are the velocities of the cannonball and the rock after the collision, respectively.

We know the mass and velocity of the cannonball before and after the collision:

m1 = 7.0 kg (mass of the cannonball before collision)

v1 = 12 m/s (velocity of the cannonball before collision)

v1' = 2.0 m/s (velocity of the cannonball after collision)

We also know the velocity of the rock after the collision:

v2' = 14 m/s (velocity of the rock after collision)

We can rearrange the equation for conservation of momentum to solve for the mass of the rock:

m2 = (m1v1 - m1v1' + m2v2') / v2'

Substituting in the values we know:

m2 = (7.0 kg x 12 m/s - 7.0 kg x 2.0 m/s) / 14 m/s

Simplifying:

m2 = 4.5 kg