Question

A 7.96 gram sample of silver reacts with oxygen to form 8.55 gram of the metal oxide. What is the formula of the metal oxide?

Answer 1

Answer:

Formula of the metal will be Ag ₂O

Explanation:

Given data

Mass of silver = 7.96 g

mass of oxygen = ?

formula of the metal = ?

Mass of metal oxide = 8.55 g

Solution

first we find out the number of moles of Ag and O

Formula to find out number of moles = mass / molar mass

Moles of Ag = 7.96g / 107.87 g.mole⁻

Moles of Ag = 0.074 mole

Moles of O = ?

mass of O = mass of metal oxide - mass of Ag

mass of O = 8.55 g - 7.96 g

mass of O = 0.59 g

Moles of O = 0.59 g / 16.00 g.mole⁻

 Moles of O = 0.037 mol

now we find out the mole ratio by dividing the smaller one

        Ag : 0

      0.074 / 0.037 : 0.037 / 0.037

       2:1

So the empirical formula of the metal silver oxide (AgO) will be Ag₂O