Question

A 70-kg man pushes a 50-kg man by a force of 50 N. By what force has the 50-kg man pushes the other man?

Answer 1

he also pushes the man with 50N as Newton's third law of motion state EVERY ACTION HAS AN EQUAL AND OPPSITE REACTIOJ

Answer 2

Given:

Mass of man1 = 70 kg

Mass of man2 = 50 kg

Force = 50 N

To find:

The force needed by man2 to push man1

Solution:

By formula,

Normal= Mass * Gravity

Where,

Gravity = 9.8 m / s

Substituting,

50 × 9.8

Normal = 490 N

To find friction,

Friction = r * Normal  

Where,  

r is coefficient of static friction

We know,

Ideally,

Frictional Force = Normal Reaction Force.  

∴ 50 = r × N  

50 = r × 490

r = 0.102

Hence,

Force = 0.102 × 70 × 9.8

Force = 69.9 N

Therefore, Force ≅ 70 N

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