A 70-kg man pushes a 50-kg man by a force of 50 N. By what force has the 50-kg man pushes the other man?
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he also pushes the man with 50N as Newton's third law of motion state EVERY ACTION HAS AN EQUAL AND OPPSITE REACTIOJ
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Given:
Mass of man1 = 70 kg
Mass of man2 = 50 kg
Force = 50 N
To find:
The force needed by man2 to push man1
Solution:
By formula,
Normal= Mass * Gravity
Where,
Gravity = 9.8 m / s
Substituting,
50 × 9.8
Normal = 490 N
To find friction,
Friction = r * Normal
Where,
r is coefficient of static friction
We know,
Ideally,
Frictional Force = Normal Reaction Force.
∴ 50 = r × N
50 = r × 490
r = 0.102
Hence,
Force = 0.102 × 70 × 9.8
Force = 69.9 N
Therefore, Force ≅ 70 N
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