Question

a 70-kg man pushes a 50-kg man by a force of 50 N. by what force has the 50-kg man the pushed the other man.

Answer 1

Given,
m₁=70kg
m₂=50kg
F=50N
The force of m1,
F=ma
50=70.a
50/70=a
5/7m/s square=a
The force of m2
F=ma
F=50N

Answer 2

Given:

Mass of man1 = 70 kg

Mass of man2 = 50 kg

Force = 50 N

To find:

The force needed by man2 to push man1

Solution:

By formula,

Normal= Mass * Gravity

Where,

Gravity = 9.8 m / s

Substituting,

50 × 9.8

Normal = 490 N

To find friction,

Friction = r * Normal  

Where,  

r is coefficient of static friction

We know,

Ideally,

Frictional Force = Normal Reaction Force.  

∴ 50 = r × N  

50 = r × 490

r = 0.102

Hence,

Force = 0.102 × 70 × 9.8

Force = 69.9 N

Therefore, Force ≅ 70 N

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