Question

a 70 kg person push 50 kg person by force of 50n. by what force 50 kg person push other

Answer 1

"GIVEN

70kg person pushes a 50kg man by a force of 50N .

So, Let force = 50N

now, normal reaction act on 50 kg man = mg

mg = 500N

we know, friction is directly proportional to normal reaction then,

fr = kN ,

k is coefficient of static friction and N is normal reaction.

now, for balancing fr = F

so, 50 = kN

50 = k × 500

k = 50/500

K = 0.1 ,

hence coefficient of static Friction = 0.1

Let F' force act by 50kg man on 70 kg man

then, F' = static Friction act on 70kg man

= coefficient of static friction × normal reaction act on 70 kg man

= 0.1 × 70 × 10 [ g = 10 m/s² ]

= 70N"