A 700 g solid cube having an edge of length 10 cm floats in watrt 2hat
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mass = 700g = 0.7 kg
volume = mass/density = 0.7/1000 (as density of water = 1000 kg/m^3)
= 7x10^-4 m^3 = 700 cm^3
Volume of cube = (10)^3 = 1000 cm^3
Volume of cube outside water = 1000-700 = 300 cm^3
i hope it will help you
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mass = 700g = 0.7 kg
volume = mass/density = 0.7/1000 (as density of water = 1000 kg/m^3)
= 7x10^-4 m^3 = 700 cm^3
Volume of cube = (10)^3 = 1000 cm^3
Volume of cube outside water = 1000-700 = 300 cm^3
i hope it will help you
Read more on Brainly.in - https://brainly.in/question/1848036#readmore
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