Question

A 75 m long train over takes a person walking at 6 kmperhour in 7.5 sec after 6.75 secA what speed was the second person traveling ​

Answer 1

Answer:

Let the speed of the train be x m/s

Speed of the 1

st

man =6 km/hr = (6×

18

5

) m/s =

3

5

m/s

⇒

(x−5/3)

75

=

2

15

⇒150=15×

3

(3x−5)

=15x−25

⇒15x=175

⇒x=

15

175

=

3

35

m/s

Let the speed of the second man be y m/s.

Then

(

3

35

−y)

75

=

4

27

⇒300=27×(

3

35−3y

)=315−27y

⇒27y=15

⇒y=

27

15

m/s =(

27

15

×

5

18

) km/hr =2 km/hr

Answer 2

Answer:2Km/Hr

Step-by-step explanation:

Let the speed of the train be x m/s  

Speed of the 1  

st

 man =6 km/hr = (6×  

18

5

​  

) m/s =  

3

5

​  

 m/s

⇒  

(x−5/3)

75

​  

=  

2

15

​  

 

⇒150=15×  

3

(3x−5)

​  

=15x−25

⇒15x=175

⇒x=  

15

175

​  

=  

3

35

​  

 m/s

Let the speed of the second man be y m/s.  

Then  

(  

3

35

​  

−y)

75

​  

=  

4

27

​  

⇒300=27×(  

3

35−3y

​  

)=315−27y

⇒27y=15

⇒y=  

27

15

​  

 m/s =(  

27

15

​  

×  

5

18

​  

) km/hr =2 km/hr

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