Math, asked by Gangotri7133, 9 months ago

A restaurant serves two special dishes — A and B to its customers consisting of 60% men and 40% women. 80% of men order dish A and the rest order B. 70% of Woman order B and the rest order A. In what ratio of dishes A to B should the restaurant prepare the two dishes?

Answers

Answered by amitnrw
9

Answer:

3:2

Step-by-step explanation:

Let say total customer = 100C

Men = 60C

Women = 40C

80% of men order dish A = (80/100)60C = 48C

Rest order Dish B = 60C - 48C = 12C

70% of Woman order B = (70/100)40C = 28C

Rest order Dish A = 40C - 28C = 12C

Dish A = 48C + 12C = 60C

DishmB = 12C + 28C = 40C

ratio of dishes A to B restaurant should prepare = 60C : 40C

= 6:4

= 3:2

Answered by ssbhushan13
3

Answer:

ok I think it is useful to you

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