A 750 kg flywheel of a steam engine having radius of gravitation of .5 m starts from rest with standing torque 1500nm tge angular acceleratorof fly wheel
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Answer:
8 rad/s^2
Explanation:
here, Mass of the flywheel, M = 750 kg
Radius of gravitation, K = 0.5 m
The starting torque of the engine is , T = 1500 nm
angular acceleration ⋉ = ?
T = 工.⋉
= MK^2.⋉
1500 = 750 x (0.5 x0.5) x ⋉
1500 = 750 x 25 x ⋉
⋉ = 1500/187.5
∴ ⋉ = 8 rad/s^2
Thus, the angular acceleration of the flywheel is 8 rad/s^2.
devendrahedarbt:
0.5*0.5=.25
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