Question

A 79 kg tight rope walker falls from a wire positioned above a safety net. If their potential energy exactly half way down from the top is 1,926 J, what height was the wire positioned above the safety net?

P.S: I'm not sure if I have to half height since it said exactly half way

Answer 1

Answer:

I don't know dear

Step-by-step explanation:

can you please follow me

Answer 2

Answer:

The height was positioned at height 4.97m above safety net

Step-by-step explanation:

Given that,

The mass of the rope walker is 79kg

$= > m = 79 \: kg$

Given that he falls from a wire above safety net and his potential energy exactly half way down from the top is 1926J.Therefore

$P.E_{ \frac{h}{2} }= 1926J$

We know the relation for potential energy at half the height which is

$P.E_{ \frac{h}{2} } = mg \frac{h}{2}$

Therefore,equating it with given potential energy we have

$mg \frac{h}{2} = 1926 \\ = > 79 \times 9.81 \times \frac{h}{2} = 1926 \\ = > h = 4.97 \: m$

Therefore,The height was positioned at height 4.97m above safety net

#SPJ2