A 7m long flagstaff is fixed on top of a tower on the horizontal plane. from a point on the ground, the angle of elevation of the top and bottom of the flafstaff are 45degrees and 60degrees respectively. find the height of the tower
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Hi ,
Draw a rough diagram according to
the problem ,
Let the distance from observer and foot of the tower = AB = x m
Height of the tower = BC = h m
Length of the flagstaff = CD = 7 m
Angle of elevation < DAB = 60 degrees
Angle of elevation = < CAB = 45
i ) from right angle triangle ABC,
< B = 90
Tan 45 = h / x
1 = h/ x
Therefore,
x = h ----------( 1 )
ii) from triangle ABD,
< B = 90
Tan 60 = ( 7 + h )/ x
Sqrt 3 = ( 7 + h )/ h from ( 1 )
Sqrt 3 × h = 7 + h
Sqrt3 × h - h = 7
h ( sqrt 3 - 1 ) = 7
h = 7 / ( sqrt 3 - 1 )
h = 7 × ( sqrt 3 + 1 )/( sqrt 3 -1)(sqrt3 +1 )
h = 7 ( sqrt 3 + 1 )/ [ ( sqrt 3 ) ^2 - 1 ]
h = 7 ( sqrt 3 + 1 )/ ( 3 - 1 )
h = 7 ( sqrt 3 + 1 )/2 m
Therefore ,
Height of the
tower( h )= 7( sqrt3 + 1 )/2m
I hope this will usful to you.
******
Draw a rough diagram according to
the problem ,
Let the distance from observer and foot of the tower = AB = x m
Height of the tower = BC = h m
Length of the flagstaff = CD = 7 m
Angle of elevation < DAB = 60 degrees
Angle of elevation = < CAB = 45
i ) from right angle triangle ABC,
< B = 90
Tan 45 = h / x
1 = h/ x
Therefore,
x = h ----------( 1 )
ii) from triangle ABD,
< B = 90
Tan 60 = ( 7 + h )/ x
Sqrt 3 = ( 7 + h )/ h from ( 1 )
Sqrt 3 × h = 7 + h
Sqrt3 × h - h = 7
h ( sqrt 3 - 1 ) = 7
h = 7 / ( sqrt 3 - 1 )
h = 7 × ( sqrt 3 + 1 )/( sqrt 3 -1)(sqrt3 +1 )
h = 7 ( sqrt 3 + 1 )/ [ ( sqrt 3 ) ^2 - 1 ]
h = 7 ( sqrt 3 + 1 )/ ( 3 - 1 )
h = 7 ( sqrt 3 + 1 )/2 m
Therefore ,
Height of the
tower( h )= 7( sqrt3 + 1 )/2m
I hope this will usful to you.
******
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