(a-8)^-4a
Factorise it
Answers
Answered by
2
To factorise:-
(a-8)²-4a
Solution:-
(a-8)²-4a
a²-16a+64-4a .......(Remember:(a-b)²=a²+b²-2ab)
a²-20a+64
a²-4a-16a+64
a(a-4)-16(a-4).......(Note:-(-16-4=20 and -16×-4=64))
(a-16)(a-4)
Correct answer:-
- (a-16)(a-4)
Answered by
4
Required Answer:-
Given to factorise:
- (a - 8)² - 4a
Solution:
We will solve this question by splitting the middle term.
Here is the solution.
(a - 8)² - 4a
= a² + 8² - 2 × a × 8 - 4a [Using identity (a - b)² = a² - 2ab + b²]
= a² - 16a - 4a + 64
a(a - 16) - 4(a - 16)
= (a - 4)(a - 16)
Now, it can't be factorised more.
Hence, the factorised form of the given polynomial is (a - 4)(a - 16)
Answer:
- The factorised form of the given polynomial is (a - 4)(a - 16)
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