Question

(a-8)^-4a
Factorise it

Answer 1

To factorise:-

(a-8)²-4a

Solution:-

(a-8)²-4a

a²-16a+64-4a .......(Remember:(a-b)²=a²+b²-2ab)

a²-20a+64

a²-4a-16a+64

a(a-4)-16(a-4).......(Note:-(-16-4=20 and -16×-4=64))

(a-16)(a-4)

Correct answer:-

• (a-16)(a-4)

Answer 2

Required Answer:-

Given to factorise:

• (a - 8)² - 4a

Solution:

We will solve this question by splitting the middle term.

Here is the solution.

(a - 8)² - 4a

= a² + 8² - 2 × a × 8 - 4a [Using identity (a - b)² = a² - 2ab + b²]

= a² - 16a - 4a + 64

a(a - 16) - 4(a - 16)

= (a - 4)(a - 16)

Now, it can't be factorised more.

Hence, the factorised form of the given polynomial is (a - 4)(a - 16)

Answer:

• The factorised form of the given polynomial is (a - 4)(a - 16)