Question

A 8-faced perfect dice being numbered from 1 to 8 is thrown once. What is
probability obtaining a number exactly divisible by 3 ?​

Answer 1

Total number of outcomes = 8.

Number of possible outcomes divisible by 3 from 1 to 8 = 2{3,6}

Hence,

Required Probability = 2/8 = 1/4

#BeBrainly

Answer 2

Answer:

$\large\bold\red{\frac{1}{4}}$

Step-by-step explanation:

Given that,

A 8 - faced dice Being numbered from 1 to 8 is thrown once.

So,

we have possible outcomes { 1, 2,3,4,5,6,7,8 }

Now,

Numbera exactly divisible by 3 are 3 and 6

Thus,

Favourable outcomes are {3,6}

Thus,

total number of possible outcomes = 8

and

number of favourable outcomes = 2

Therefore,

Probability of getting numbers exactly divisible by 3 is,

$probability = \frac{number \: of \: favourable \: outcomes}{total \: number \: of \: possible \: outcomes} \\ \\ = > p = \frac{2}{8} \\ \\ = > p = \frac{1}{4}$

Hence,

$\large\bold{\frac{1}{4}}$ is the resultant probability of getting a number exactly divisible by 3.