Question

a 80 kg box is pushef acrosss the floor of certain distance to attain k.e. of 160 j.if the pushing force is 375 N ,the force of friction between the box and floor is 25 N and it is starting from the rest then calculate 1) its initial velocity .2) net force acting on the box.3) acceleration of the box 4) the distance up to which the box should be pushed .5) what is the work done during the process? plzz give ans fast tomorrow i hv exam

Answer 1

total force = force applied - friction ( friction take place in negative direction) = 375 - 25 = 350 N is net force acting on it

F = ma 350 = 80 a

a = 350/80 is acceleration acting on box Ek = 1/2v2 m 160 = 1/2 v2 80

so velocity is 2 

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