A 800 turn coil of effective area 0.05 m2 is kept
perpendicular to a magnetic field 5 x 10-5 T. When
the plane of the coil is rotated by 90° around any
of its coplanar axis in 0.1 s, the emf induced in the
coil will be
Answers
Answered by
3
Given:
A 800 turn coil of effective area 0.05 m² is kept
perpendicular to a magnetic field 5 x 10-5 T. The plane of the coil is rotated by 90° in 0.1 s.
To find:
EMF induced in coil.
Calculation:
According to Faraday's Law of Electromagnetic Induction , the EMF induced in a coil is equal to the rate of change of magnetic flux.
Change in magnetic flux:
Time taken = 0.1 seconds.
Let EMF be denoted as E:
So , final answer is :
Answered by
1
Explanation:
Given A 800 turn coil of effective area 0.05 m2 is kept perpendicular to a magnetic field 5 x 10-5 T. When the plane of the coil is rotated by 90° around any of its coplanar axis in 0.1 s, the emf induced in the coil will be
- Total turns N = 800
- Area = 0.05 m^2 = 5 x 10^-2 m^2
- Magnetic field strength B = 5 x 10^-5 T
- Time Δt = 0.1 s
- We need to find emf induced in the coil.
- So induced emf = - Δφ / Δt
- So Δφ = φ final – φ initial
- So φ final = 0 and φ initial = N (B.A)
- = 800 x (5 x 10^-5 x 5 x 10^-2)
- = 800 x 25 x 10^-7
- = 20000 x 10^-7
- = 2 x 10^-3
- So emf induced = - Δφ / Δt
- = - (0 – 2 x 10^-3) / 0.1
- = 2 x 10^-3 / 0.1
- = 0.02 V
- So induced emf in the coil will be 0.02 V
Reference link will be
https://brainly.in/question/7875338
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