Physics, asked by chithravel, 9 months ago

A 800 turn coil of effective area 0.05 m2 is kept
perpendicular to a magnetic field 5 x 10-5 T. When
the plane of the coil is rotated by 90° around any
of its coplanar axis in 0.1 s, the emf induced in the
coil will be​

Answers

Answered by nirman95
3

Given:

A 800 turn coil of effective area 0.05 m² is kept

perpendicular to a magnetic field 5 x 10-5 T. The plane of the coil is rotated by 90° in 0.1 s.

To find:

EMF induced in coil.

Calculation:

According to Faraday's Law of Electromagnetic Induction , the EMF induced in a coil is equal to the rate of change of magnetic flux.

Change in magnetic flux:

 \therefore \: \Delta \phi = n(BA) - 0

 =  >  \: \Delta \phi = 800 \times (5 \times  {10}^{ - 5}  \times 0.05) - 0

 =  >  \: \Delta \phi = 2  \times  {10}^{ - 3}

Time taken = 0.1 seconds.

Let EMF be denoted as E:

 \therefore  \: E =   \:  \dfrac{\Delta \phi }{t}

 =  >   \: E =   \:  \dfrac{2 \times  {10}^{ - 3} }{0.1}

 =  >   \: E =   \:  \dfrac{2 \times  {10}^{ - 3} }{ {10}^{ - 1} }

 =  >   \: E =   \: 20 \times  {10}^{ - 3}  \: volt

 =  >   \: E =   \: 20  \: mV

So , final answer is :

 \boxed{ \bold{ \large{   \: E =   \: 20  \: mV }}}

Answered by knjroopa
1

Explanation:

Given A 800 turn coil of effective area 0.05 m2 is kept perpendicular to a magnetic field 5 x 10-5 T. When  the plane of the coil is rotated by 90° around any  of its coplanar axis in 0.1 s, the emf induced in the  coil will be

  • Total turns N = 800
  • Area = 0.05 m^2 = 5 x 10^-2 m^2
  • Magnetic field strength B = 5 x 10^-5 T
  • Time Δt = 0.1 s
  • We need to find emf induced in the coil.
  • So induced emf = - Δφ / Δt
  • So Δφ = φ final – φ initial
  • So φ final = 0 and φ initial = N (B.A)
  •                                           = 800 x (5 x 10^-5 x 5 x 10^-2)
  •                                           = 800 x 25 x 10^-7
  •                                          = 20000 x 10^-7
  •                                         = 2 x 10^-3
  • So emf induced = - Δφ / Δt
  •                          = - (0 – 2 x 10^-3) / 0.1  
  •                          = 2 x 10^-3 / 0.1
  •                         = 0.02 V
  • So induced emf in the coil will be 0.02 V

Reference link will be

https://brainly.in/question/7875338

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