A 8000 kg engine pulls a train of 5 wagons, each of 2000 kg, along a horizontal track. If the engine exerts a force of 40000 N and the track offers a friction force of 5000 N, then calculate the force of wagon1 on wagon 2
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Net accelerating force =force by engine - frictional force
=40000-5000=35000
Mass of engine =8000kg
" " wagons =5*2000kg=10000kg
Mass of engine +mass of wagons =18000kg
F=35000N
M=18000kg
a=F/m
=35,000/18000
=35/18m/s^2
Force of wagon 1 on wagon 2=mass of 4 wagons *acceration
=4*2000*35/18
=8000*35/18
=15555. 56N
15555.6N(approx)
Note :This is a question from ncert. If you search on net you may find different answers. But the back answer is 15556 N. I think it is printing mistake.
=40000-5000=35000
Mass of engine =8000kg
" " wagons =5*2000kg=10000kg
Mass of engine +mass of wagons =18000kg
F=35000N
M=18000kg
a=F/m
=35,000/18000
=35/18m/s^2
Force of wagon 1 on wagon 2=mass of 4 wagons *acceration
=4*2000*35/18
=8000*35/18
=15555. 56N
15555.6N(approx)
Note :This is a question from ncert. If you search on net you may find different answers. But the back answer is 15556 N. I think it is printing mistake.
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