Question

A 8000kg engine pulls a train of 5wagons . each of 2000kg.along ahorizontal truck . If the engine exerts a force of 40000N and the truck offers a frictional force of 5000N then calculate ;
a. The net accelerating forces;
b. The acceleration of the train;and
c. The force of wagon 1 on wagon 2.

Answer 1

Explanation:

f=ma so , the force of wagon 1 on wagon 2 =4×2000×3.5

Answer 2

Answer:-

Explanation:-

Force exerted by the engiene F¹ =40,000N.

Frictional force exerted by the track

F² = - 5000N.

Negative sign shows that is friction is opposite to the direction of motion.

1.Therefore,net accelerating force

F = F¹ + F²

F = 40,000 - 5000

F = 35,000N.

$\boxed{\boxed{F = 35,000N}}$

so,net accelerating force is 35,000N

2.Mass of each wagon of the train = 2000kg.

Number of wagons =5

therefore,

Mass of the train(without engine) = 2000 ×5 = 10,000kg.

Net accelerating force of the train is = ?.

F = 35,000N.

M = 10,000kg.

from,

$F = ma$

$a = \frac{F}{m}$

$a = \frac{35000}{10000}$

$a = 3.5$

$\boxed{\boxed{a=3.5 m/s^2}}$

so,the acceleration of train is 3.5m/s^2.

3.Mass of one wagon(m¹) = 2000kg.

Acceleration of the train = 3.5m/s^2.

Frictional resistance = 5000 ×2000 ×4 ÷10,000

Frictional resistance = 4,000N.

Accelerating force on 4 wagons = 2000 × 4 × 3.5 = 28,000N

Now,

F' = Frictional resistance + Accelerating force on 4 wagons

F' = 4000 + 28000

F' = 32,000N.

$\boxed{\boxed{F' = 32,000N}}$

so,the force of wagon 1 on wagon 2 is 32,000N.