Question

A rocket launched at 5.00 p.m. from Thumba Rocket Launching Station. It's velocity was 12 km/s. What distance distance did it cover during the time interval 5:32 p.m. to quarter to six p.m. ?​

Answer 1

Step-by-step explanation:

Total time from 5:32 p.m. to quarter to six p.m. (5:45 pm) =13 minutes

= 13 x 60 seconds = 780 seconds

Speed of rocket = 12 km/s

$Distance = speed \times time \\ = 12 \times 780 \\ = 9360 \: km$

Thus, the rocket covered a distance of 9360 km during the time interval 5:32 p.m. to quarter to six p.m.

Answer 2

Step-by-step explanation:

Total time from 5:32 p.m. to quarter to six p.m. (5:45 pm) =13 minutes

= 13 x 60 seconds = 780 seconds

Speed of rocket = 12 km/s

\begin{gathered}Distance = speed \times time \\ = 12 \times 780 \\ = 9360 \: km \\ \end{gathered}

Distance=speed×time

=12×780

=9360km

Thus, the rocket covered a distance of 9360 km during the time interval 5:32 p.m. to quarter to six p.m.