Question

A) 9 & 3
B) 6 & 3
Mass of oxygen present in 10 moles of H_S20is
C) 9 56 xơ
TI​

Answer 1

Answer:

1 mole of Na

2

CO

3

=106g

moles in 10.6g of Na

2

CO

3

=10.6/106=0.1 mole

106g contain atoms of oxygen =3×6.022×10

23

10.6 contain atoms =0.1×3×6.022×10

23

=1.8×10

23

atoms.

Answer 2

mole of Na

2

CO

3

=106g

moles in 10.6g of Na

2

CO

3

=10.6/106=0.1 mole

106g contain atoms of oxygen =3×6.022×10

23

10.6 contain atoms =0.1×3×6.022×10

23

=1.8×10

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