A 9 V battery is connected in series with a resistor .The terminal voltage is found to be 8 V.Current through the circuit is measured as 5 A. What is the internal resistance of the battery?
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Explanation:
Internal resistance of battery is 0.2ohm .This is right answer.
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Concept
Electric current is the Ratio of the voltage and the resistance
Given
Given that the voltage are 9V and 8V and the current given is 5 A
Find
We need to find the value of Resistance
Solution
The current given is 5 A
The Voltage given is 9V and 8V
According to the formula I = V/R
Therefore R = V/I
V = 9V - 8V = 1
So R = 1/5
Therefore the resistance is 0.2Ω
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