Question

a 9 volt battery is connected in series with the resistor 0.2ohm,0.3ohm,0.4ohm,0.5ohmand12ohmr respectively.How much current would flow through 12ohm resistor

Answer 1

restistance in series = r1 +r2 +r3 + r4 + r5

0.2+ 0.3+0.4+0.5+12.0=23.4

then find out current

Answer 2

Answer:

Explanation:

A battery of 9V is connected in series with resistors of 0.2 ohm, 0.3 ohm, 0.4 ohm, 0.5 ohm and 12 ohm, respectively. How much current would flow through the 12 ohm resistor? Equivalent resistance in series = 0.2 + 0.3 + 0.4 +0.5 + 12 =13.4 ohms.