Find the sum of the terms of the arithmetic sequence with first term 50 common difference 11 and 101 terms
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Step-by-step explanation:
Given: a = 50 , d = 11 , n = 101
Sn = n/2[a + an]
= 101/2[50 + 50 +100(11)]
= 50.5[100 + 1100]
= 50.5[1200]
= 30,30,000..
Hope it helps
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