Physics, asked by jiminsh, 6 months ago

A 900 Kg car moving at 10 m/s takes a turn around a circle with a radius of 25.0 m. Determine the acceleration and net force acting upon the car.

Answers

Answered by sivsang5
21

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Explanation:

When the car turns around circle, it experiences centripetal acceleration,

a=v²/r

=100/25

which gives: 4m/s²

Net force acting upon the car,

F=ma

=900×4

F=3600N

Answered by nirman95
9

Given:

A 900 Kg car moving at 10 m/s takes a turn around a circle with a radius of 25.0 m.

To find:

  • Net acceleration
  • Net force acting on the car

Calculation:

Here, the net acceleration is the Centripetal Acceleration while moving on the circular path:

a_{c} =  \dfrac{ {v}^{2} }{r}

 \implies \: a_{c} =  \dfrac{ {10}^{2} }{25}

 \implies \: a_{c} =  \dfrac{100}{25}

 \implies \: a_{c} =  4 \: m/ {s}^{2}

Now, centripetal force will be :

F = 900 \times 4

 \implies \: F = 3600 \: N

So, acceleration is 4 m/ and force is 3600 N.

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