Question

a×a+a+1=0,then the value of a×a×a×a×a+a×a×a×a+1​

Answer 1

Answer:

a"3

Step-by-step explanation:

because the power of 3 is for the space diagonal force

Answer 2

Answer:

a2+a+1=0

a2+1/2a+1/2a+1=0

1a/2(1a/2+1)1(1a/2+1)=0

(1a/2+1)(1a/2+1)=0

a=-2

-2ka power5+-2ka power4+1