Question

A+A+A+A+A+A+B+B+B+B=78731156. If B is twice of A find the value of 2(A+B).




(A) 33741974
(B) 43741974
(C) 33741924
(D) 33741024
(E) None of these

Answer 1

(A x 6) + (B x 4) = 78731156

= (A x 6) + (2A x 4) = 78731156

= 6A + 8A = 78731156

= 14A = 78731156

A = 78731156 ÷ 14 = 5623654

2(A + B)

= 2(A + 2A)

= 2 x 3A

= 6A = 6 x 5623654 = 33741924

∴ The answer is option (C).

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Answer 2

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