Question

a×a×a+b×b×b+c×c×c-3abc/a+b+c=​

Answer 1

Answer:

a^3+b^3=c^-3abc/a+b+c

Step-by-step explanation:

a^3+b^3+c^3-3abc is same as x^3+y^3+z^3-3xyz

therefore, (a+b+c)(a^2+y^2+z^2-ab-bc-ca)/a+b+c

a^2+b^2+c^2-ab-bc-ca

Answer 2

Answer:

a³+b³+c³-3abc/a+b+c

=(a+b+c)(a²+b²+c²-ab-bc-ca) /a+b+c

=a²+b²+c²-ab-bc-ca