a.a-a+i=0 then the inverse of a is
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a.a-a+i=0
a(a-1) + i = 0
a(a-1) = -i
a = -i / (a-1)
1/a = -(a-1) / i
1/a = (1-a) / i
inverse of a = (1-a) / i
a(a-1) + i = 0
a(a-1) = -i
a = -i / (a-1)
1/a = -(a-1) / i
1/a = (1-a) / i
inverse of a = (1-a) / i
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inverse of a by my calculation is = (1-a)/i
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