A
A car running at 72 km/h
stops after covering
e distence of
lkm calculate the retardation?
Answers
Answered by
0
Answer:α=−25.5 rad/s
2
Step-by-step explanation:Initial speed, v=72 km/h
⟹v=
3600
72×10
3
⟹v=20 m/s
Distance, 2r=50 cm
⟹r=25×10
−2
m
Angular displacement, θ=20×2π
⟹θ=40π rad
Initial angular velocity, ω=
r
v
⟹ω=
25×10
−2
20
⟹ω=
5
4
×10
2
⟹ω=80 rad/s
Final angular velocity, ω
′
=0 rad/s
From kinematics:
ω
′2
−ω
2
=2αθ (where α is angular acceleration)
⟹0−6400=2α×40π
⟹α=
80π
−6400
⟹α=−25.5 rad/s
2
Similar questions