Question

(a) A current of 0.01 A is drawn by a filament of an electric bulb. Calculate
the number of electrons passing through a cross section of the filament in
16 seconds. (e = 1.6 x 10 to. the power-19C)
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Answer 1

Answer:

When one coulomb charge passes through any cross section of the wire per second,the current passing is one ampere. n=1/(1.6X10^-19)=6.25X10^18. This number of electrons passes through cross section of a wire carrying 1A current. A current of 2A flows through a copper wire

Answer 2

Explanation:

Hi/ho is Ur correct answer

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