a) A cylinder, hemisphere and cone stand on equal base and same height, the Volume ratio is
3:2:1
b) The radius of a solid sphere is 24 cm. 8 spheres can be made from it of 12cm radius
c) radius of the cone is doubled and height is halved, the volume will be halved
d) A river 10m deep and 40m wide is flowing at the rate of 2m per min. 48000m3
water will flow
into the sea from river
e) A cylinder radius is halved and height is doubled, the volume will become halved
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Answer:
Given.
A cone, a hemisphere, and a cylinder stand on equal bases.
Hence radius of base of cone = radius of hemisphere = radius of cylinder=r
And,
They also have same height =h
Hight of cone =h
Hight of cylinder=h
Hight of Hemisphere r=h (r is the radius of sphere)
Now,
Volume of cone V
C
=
3
1
πr
2
h...….(1)
Volume of hemisphere V
H
=
3
2
πr
2
×r
=
3
2
πr
2
×h
V
H
=
3
2
πr
2
h…….(2)
Volume of cylinder V
c
=πr
2
h...…..(3)
From equation 1,2 and 3
V
C
:V
H
:V
c
=
3
1
πr
2
h:
3
2
πr
2
h:πr
2
h
V
C
:V
H
:V
c
=
3
1
:
3
2
:1
V
C
:V
H
:V
c
=1:2:3
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